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5n^2-44n+32=0
a = 5; b = -44; c = +32;
Δ = b2-4ac
Δ = -442-4·5·32
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-36}{2*5}=\frac{8}{10} =4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+36}{2*5}=\frac{80}{10} =8 $
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